NEET-XII-Physics
42: Photoelectric Effect and Wave Particle Duality
- #2Calculate the momentum of a photon of light of wavelength 500 nm.Ans : Given:
Wavelength of light, `` \lambda `` = 500 nm
Planck's constant, h = 6.63`` \times ``10`` -34`` J-s
Momentum of a photon of light,
`` p=\frac{h}{\lambda }``
`` =\frac{6.63\times {10}^{-34}}{500\times {10}^{-9}}``
`` =\frac{6.63}{5}\times {10}^{-27}``
`` =1.326\times {10}^{-27}``
`` =1.33\times {10}^{-27}\,\mathrm{\,kg\,}-m/\,\mathrm{\,s\,}``
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