Qstnid -Iv-35-figure Shows A Wire Sliding On Two Parallel, Conducting Rails Placed At A Separation L. A Magnetic Field B Exists In A Direction Perpendicular To The Plane Of The Rails. What Force Is Necessary To Keep The Wire Moving At A Constant Velocity V ? <Span Style="background-color: #Ffff00;">figure</span></span> - 38: Electromagnetic Induction - Neet-xii-physics

Home Learn Fast select Course

Show Unit/Chapter Change Unit Change Subject Last Menu

NEET-XII-Physics

38: Electromagnetic Induction

with Solutions - page 8

Qstn# iv-35 Prvs-Qstn Next-Qstn

#35
Figure shows a wire sliding on two parallel, conducting rails placed at a separation l. A magnetic field B exists in a direction perpendicular to the plane of the rails. What force is necessary to keep the wire moving at a constant velocity v ?
Figure
Ans : Because the force exerted by the magnetic field on the rod is given by F_magnetic = ilB, the direction of this force is opposite to that of the motion of the rod.
Now, let the external force on it be F.
Because the velocity is constant, the net force acting on the wire must be zero.
Thus, F = F_magnetic = ilB is acting in the direction of the velocity.
Page No 308: