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NEET-XII-Physics

38: Electromagnetic Induction

with Solutions - page 5
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  • #14
    The north pole of a magnet is brought down along the axis of a horizontal circular coil (figure). As a result, the flux through the coil changes from 0.35 weber to 0.85 weber in an interval of half a second. Find the average emf induced during this period. Is the induced current clockwise or anticlockwise as you look into the coil from the side of the magnet ?
    Figure
    Ans : Given:
    Initial flux, ϕ1 = 0.35 weber
    Final flux ϕ2 = 0.85 weber
    ∴ Δϕ = ϕ2 - ϕ1
    = (0.85 - 0.35) weber
    = 0.5 weber
    Also,
    Δt = 0.5 s
    The magnitude of the induced emf is given by
    `` e=\frac{∆\,\mathrm{\,\varphi \,}}{∆t}=\frac{0.5}{0.5}=1\,\mathrm{\,V\,}``

    The induced current is anti-clockwise when seen from the side of the magnet.
    Page No 307: