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NEET-XII-Physics
38: Electromagnetic Induction
- #14The north pole of a magnet is brought down along the axis of a horizontal circular coil (figure). As a result, the flux through the coil changes from 0.35 weber to 0.85 weber in an interval of half a second. Find the average emf induced during this period. Is the induced current clockwise or anticlockwise as you look into the coil from the side of the magnet ?
FigureAns : Given:
Initial flux, ϕ1 = 0.35 weber
Final flux ϕ2 = 0.85 weber
∴ Δϕ = ϕ2 - ϕ1
= (0.85 - 0.35) weber
= 0.5 weber
Also,
Δt = 0.5 s
The magnitude of the induced emf is given by
`` e=\frac{∆\,\mathrm{\,\varphi \,}}{∆t}=\frac{0.5}{0.5}=1\,\mathrm{\,V\,}``

The induced current is anti-clockwise when seen from the side of the magnet.
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