NEET-XII-Physics

37: Magnetic Properties of Matter

with Solutions - page 2
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  • #1
    The magnetic intensity H at the centre of a long solenoid carrying a current of 2.0 A, is found to be 1500 A m-1. Find the number of turns per centimetre of the solenoid.
    Ans : Here,
    Current in the solenoid, I = 2 A
    Magnetic intensity at the centre of long solenoid, H = 1500 Am-1
    Magnetic field produced by a solenoid`` \left(B\right)`` is given by
    B = µ0ni ...(1)
    Here, n = number of turns per unit length
    i = electric current through the solenoid
    Also, the relation between magnetic field strength`` \left(B\right)`` and magnetic intensity`` \left(H\right)`` is given by
    H = `` \frac{B}{{\,\mathrm{\,\mu \,}}_{0}}`` ...(2)
    From equations (1) and (2), we get:
    H = ni
    ⇒ 1500 A/m = n × 2
    ⇒ n = 750 turns/meter
    ⇒ n = 7.5 turns/cm
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