NEET-XII-Physics
32: Electric Current in Conductors
- #1-aWrite the dimensional formulae for A, B and C. (b) If the numerical values of A, B and C are 5, 3 and 1, respectively, in S.I units, find the value of the current at t = 5 s. (b) If the numerical values of A, B and C are 5, 3 and 1, respectively, in S.I units, find the value of the current at t = 5 s.Ans : Amount of charge,
Q(t) = At2 + Bt + C
We can only add the terms with the same dimensions. So, all the individual terms will have dimensions equal to the dimensions of the charge.
Comparing the dimensions of each term separately, we get:
`` A{t}^{2}=Q``
`` \Rightarrow A=\frac{Q}{{t}^{2}}``
`` Q=It``
`` \Rightarrow A=\frac{I}{t}=\left[{\,\mathrm{\,AT\,}}^{-1}\right],``
where I = current through the wire
Now,
`` Bt=Q``
`` \Rightarrow B=\frac{Q}{t}=I=\left[\,\mathrm{\,A\,}\right]``
Also,
`` C=Q``
`` \Rightarrow C=\left[\,\mathrm{\,AT\,}\right]`` (b) Current I = rate of flow of charge
`` \Rightarrow I=\frac{\,\mathrm{\,d\,}Q}{\,\mathrm{\,d\,}t}=\frac{\,\mathrm{\,d\,}}{\,\mathrm{\,d\,}t}\left(A{t}^{2}+Bt+C\right)``
`` \Rightarrow I=2At+B``
`` A=5,B=3\,\mathrm{\,and\,}t=5\,\mathrm{\,s\,}``
`` \Rightarrow I=2\times 5\times 5+3=53\,\mathrm{\,A\,}``
Page No 198: (b) Current I = rate of flow of charge
`` \Rightarrow I=\frac{\,\mathrm{\,d\,}Q}{\,\mathrm{\,d\,}t}=\frac{\,\mathrm{\,d\,}}{\,\mathrm{\,d\,}t}\left(A{t}^{2}+Bt+C\right)``
`` \Rightarrow I=2At+B``
`` A=5,B=3\,\mathrm{\,and\,}t=5\,\mathrm{\,s\,}``
`` \Rightarrow I=2\times 5\times 5+3=53\,\mathrm{\,A\,}``
Page No 198:
- #1-bIf the numerical values of A, B and C are 5, 3 and 1, respectively, in S.I units, find the value of the current at t = 5 s.Ans : Current I = rate of flow of charge
`` \Rightarrow I=\frac{\,\mathrm{\,d\,}Q}{\,\mathrm{\,d\,}t}=\frac{\,\mathrm{\,d\,}}{\,\mathrm{\,d\,}t}\left(A{t}^{2}+Bt+C\right)``
`` \Rightarrow I=2At+B``
`` A=5,B=3\,\mathrm{\,and\,}t=5\,\mathrm{\,s\,}``
`` \Rightarrow I=2\times 5\times 5+3=53\,\mathrm{\,A\,}``
Page No 198: