NEET-XII-Physics
32: Electric Current in Conductors
- #10A uniform wire of resistance 50 Ω is cut into 5 equal parts. These parts are now connected in parallel. The equivalent resistance of the combination is
(a) 2 Ω
(b) 10 Ω
(c) 250 Ω
(d) 6250 ΩdigAnsr: aAns : (a) 2 Ω
Resistance of a wire is directly proportional to its length.
So, when we cut the wire into 5 equal parts, the resistance of each part will be 10 Ω.
On connecting these wires in parallel, the net resistance will be
`` \frac{1}{R}=\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}``
`` \Rightarrow R=2\,\mathrm{\,\Omega \,}``
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