NEET-XII-Physics

31: Capacitors

with Solutions - page 2
Qstn# ii-12 Prvs-QstnNext-Qstn
  • #12
    Three capacitors of capacitances 6 µF each are available. The minimum and maximum capacitances, which may be obtained are
    (a) 6 µF, 18 µF
    (b) 3 µF, 12 µF
    (c) 2 µF, 12 µF
    (d) 2 µF, 18 µF.
    digAnsr:   d
    Ans :
    (d) 2 µF, 18 µF
    The minimum capacitance can be obtained by connecting all capacitors in series. It can be calculated as follows:
    `` \frac{1}{C}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{1}{2}``

    `` \Rightarrow ``
    C = 2 µF
    The maximum capacitance can be obtained by connecting all capacitors in parallel. It can be calculated as follows:
    C = 6 + 6 + 6 = 18 µF

    Page No 164: