NEET-XII-Physics
29: Electric Field and Potential
- #14Find the ratio of the electrical and gravitational forces between two protons.Ans : We know that the mass of a proton, m = 1.67 × 10-27 kg
Charge on a proton, q = 1.6 × 10-19 C
Gravitational constant, `` \,\mathrm{\,G\,}=6.67\times {10}^{-11}\,\mathrm{\,N\,}-{\,\mathrm{\,m\,}}^{2}/{\,\mathrm{\,kg\,}}^{2}``
Electrostatic force,
`` {F}_{e}=\frac{1}{4\,\mathrm{\,\pi \,}{\epsilon }_{0}}\frac{{q}^{2}}{{r}^{2}}``
`` ``
Gravitational force,
`` {F}_{g}=G\frac{{m}^{2}}{{r}^{2}}``
`` \Rightarrow \frac{{F}_{e}}{{F}_{g}}=\frac{{q}^{2}}{4\,\mathrm{\,\pi \,}{\epsilon }_{0}G{m}^{2}}``
`` =\frac{9\times {10}^{9}\times {\left(1.6\times {10}^{-19}\right)}^{2}}{6.67\times {10}^{-11}\times {\left(1.67\times {10}^{-27}\right)}^{2}}``
`` =1.23\times {10}^{36}``
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