NEET-XII-Physics
29: Electric Field and Potential
- #5Find the electric force between two protons separated by a distance of 1 fermi (1 fermi = 10-15 m). The protons in a nucleus remain at a separation of this order.Ans : We know:
Charge on a proton, q = 1.6 × 10-19 C
Given, separation between the charges, r = 10-15 m
By Coulomb's Law, electrostatic force,
`` F=\frac{1}{4\,\mathrm{\,\pi \,}{\epsilon }_{0}}\frac{{q}_{1}{q}_{2}}{{r}^{2}}``
`` \Rightarrow F=9\times {10}^{9}\times \frac{{\left(1.6\times {10}^{-19}\right)}^{2}}{{\left({10}^{-15}\right)}^{2}}``
`` \Rightarrow F=230\,\mathrm{\,N\,}``
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