NEET-XII-Physics
29: Electric Field and Potential
- #1Find the dimensional formula of ε0.Ans : By Coulomb's Law,
`` F=\frac{1}{4\,\mathrm{\,\pi \,}{\epsilon }_{0}}\frac{{q}_{1}{q}_{2}}{{r}^{2}}``
`` \Rightarrow {\epsilon }_{0}=\frac{1}{4\,\mathrm{\,\pi \,}F}\frac{{q}_{1}{q}_{2}}{{r}^{2}}``
Using [F] = [MLT-2]
[r] = [M0L1T0]
[q] = [M0L0T1A1], we get
[ε0] = [M-1L-3T4A2]
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