NEET-XII-Physics
24: Kinetic Theory of Gases
- #82 g of hydrogen is sealed in a vessel of volume 0.02 m3 and is maintained at 300 K. Calculate the pressure in the vessel.Ans : Given:
Mass of hydrogen, m = 2 g
Volume of the vessel, V = 0.02 m3
Temperature in the vessel, T = 300 K
Molecular mass of the hydrogen, M = 2 u
No of moles, n = `` \frac{m}{M}=\frac{2}{2}``= 1 mole
Rydberg's constant, R = 8.3 J/Kmol
From the ideal gas equation, we get
PV = nRT
`` \Rightarrow P=\frac{nRT}{V}``
`` \Rightarrow P=\frac{1\times 8.3\times 300}{0.02}``
`` \Rightarrow ``P = 1.24 × 105 Pa