NEET-XII-Physics

24: Kinetic Theory of Gases

with Solutions - page 2
Qstn# ii-13 Prvs-QstnNext-Qstn
  • #13
    The process on an ideal gas, shown in figure, is
    (a) isothermal
    (b) isobaric
    (c) isochoric
    (d) none of these.
    Figure
    digAnsr:   c
    Ans : According to the graph, P is directly proportional to T.
    Applying the equation of state, we get
    PV = nRT
    `` \Rightarrow P=\frac{nR}{V}T``
    `` ``
    `` \,\mathrm{\,Given\,}:P\alpha T``
    `` \,\mathrm{\,This\,}\,\mathrm{\,means\,}\frac{\,\mathrm{\,n\,}\,\mathrm{\,R\,}}{\,\mathrm{\,V\,}}\,\mathrm{\,is\,}\,\mathrm{\,a\,}\,\mathrm{\,constant\,}.\,\mathrm{\,So\,},\,\mathrm{\,V\,}\,\mathrm{\,is\,}\,\mathrm{\,also\,}\,\mathrm{\,a\,}\,\mathrm{\,constant\,}.``
    Constant V implies the process is isochoric.
    Thus,
    (c) is the correct answer.