NEET-XII-Physics
24: Kinetic Theory of Gases
- #11The rms speed of oxygen molecules in a gas is v. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become
(a) v
(b)
v2
(c) 2v
(d) 4v.digAnsr: cAns : `` \,\mathrm{\,Given\,}:\,\mathrm{\,v\,}=\sqrt{\frac{3\,\mathrm{\,RT\,}}{32}}``
`` \,\mathrm{\,Suppose\,}\,\mathrm{\,the\,}\,\mathrm{\,new\,}\,\mathrm{\,rms\,}\,\mathrm{\,speed\,}\,\mathrm{\,be\,}\,\mathrm{\,v\,}\text{'}.``
`` \,\mathrm{\,Molecule\,}\,\mathrm{\,dissociate\,},M=16``
`` ``
`` v\text{'}=\sqrt{\frac{3R\left(2T\right)}{16}}``
`` =\sqrt{\frac{3R\left(4T\right)}{32}}``
`` =2\sqrt{\frac{3RT}{32}}=2v``
Thus,
(c) is the correct answer.