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NEET-XII-Physics
23: Heat and Temperature
- #8A platinum resistance thermometer reads 0° when its resistance is 80 Ω and 100° when its resistance is 90 Ω.
Find the temperature at the platinum scale at which the resistance is 86 Ω.Ans : Given:
Resistance at 0oC, R0 = 80 `` \,\mathrm{\,\Omega \,}``
Resistance at 100oC, R100 = 90 `` \,\mathrm{\,\Omega \,}``
Let t be the temperature at which the resistance (Rt) is 86 `` \,\mathrm{\,\Omega \,}``.
`` t=\frac{{R}_{t}-{R}_{0}}{{R}_{100}-{R}_{0}}\times 100``
`` \Rightarrow t=\frac{86-80}{90-80}\times 100``
`` \Rightarrow t=\frac{6}{10}\times 100``
`` \Rightarrow t=60°``
Therefore, the resistance is 86 `` \,\mathrm{\,\Omega \,}`` at 60oC.
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