NEET-XII-Physics
23: Heat and Temperature
- #6As the temperature is increased, the time period of a pendulum
(a) increases proportionately with temperature
(b) increases
(c) decreases
(d) remains constantdigAnsr: bAns : (b) increases
In general, the time period of a pendulum,t, is given by
`` t=\frac{1}{2\pi }\sqrt{\frac{l}{g}}``.
When the temperature (T) is increased, the length of the pendulum (l) is given by,
`` l={l}_{0}(1+\alpha T)``,
where l0 = length at 0 oC
`` \alpha ``= linear coefficient of expansion.
Therefore, the time period of a pendulum will be
`` t=\frac{1}{2\pi }\sqrt{\frac{{l}_{0}(1+\alpha T)}{g}}``
Hence, time period of a pendulum will increase with increase in temperature.
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