NEET-XII-Physics
qstns with ansrs year:2022
- #13In the given nuclear reaction, the element `` X `` is: `` { }_{11}^{22} Na \rightarrow X + e ^{+}+v ``
(A) `` { }_{12}^{22} Mg ``
(B) `` { }_{11}^{23} Na ``
(C) `` { }_{10}^{23} Ne ``
(D) `` { }_{10}^{22} Ne ``digAnsr: DAns : `` { }_{11}^{22} Na \longrightarrow X +e^{+}+v ``
This is `` \beta^{+}- `` decay
`` { }_{11}^{22} Na \longrightarrow{ }_{10}^{22} Ne + e ^{+}+ v ``