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NEET-XII-Physics
neet 2020 questions with solutions year:2020
- #24The energy required to break one bond in DNA is `` 10^{-20}J `` . This value in eV is nearly
(A)6
(B)0.6
(C)0.06
(D)0.006
digAnsr: CAns : `` 1\,eV=1.6\times 10^{-19}\\,J ``
`` 1\,J=\frac{1}{1.6\times 10^{-19}}eV ``
`` 10^{-20}\,J=\frac{10^{-20}}{1.6\times 10^{-19}}eV ``
`` =0.06\,eV ``