NEET-XII-Physics
P1 year:2019
- #13An electron is accelerated through a potential
difference of 10,000 V. Its de Broglie
wavelength is, (nearly) : (``m_e = 9 × 10^{-31}`` kg)
(1) ``12.2 × 10^{-13}`` m
(2) ``12.2 × 10^{-12}`` m
(3) ``12.2 × 10^{-14}`` m
(4) 12.2 nmdigAnsr: 2Ans : ( 2 )
Sol. For an electron accelerated through a
potential V,
``\lambda``=``\frac{12.27} {\sqrt v}`` Å= ``\frac{12.27 X 10^{-10} }{\sqrt 10000}``=``12.27 X 10 ^{-12} ``m