NEET-XII-Physics

P1 year:2019

with Solutions -
  • #11
    Two similar thin equi-convex lenses, of focal
    length f each, are kept coaxially in contact
    with each other such that the focal length of
    the combination is ``F_1``. When the space
    between the two lenses is filled with
    glycerine (which has the same refractive index
    (μ = 1.5) as that of glass) then the equivalent
    focal length is ``F_2``. The ratio ``F_1:F_2``
    will be :
    (1) 2 : 1
    (2) 1 : 2
    (3) 2 : 3
    (4) 3 : 4
    digAnsr:   2
    Ans : ( 2 )
    Sol.
    Equivalent focal length in air =
    ``\frac1F_1 = \frac1f + \frac1f = frac2f``
    m1 png
    When glycerin is filled inside, glycerin lens
    behaves like a diverging lens of focal length (-f)=``\frac1F_2 = \frac1f + \frac1f- \frac1f= frac1f``
    therefore ``\frac{F_1}{F_2}=\frac12``