Qstnid -43- A Parallel Plate Capacitor Of Capacitance 20 Μf Is Being Charged By A Voltage Source Whose Potential Is Changing At The Rate Of 3 V/s. The Conduction Current Through The Connecting Wires, And The Displacement Current Through The Plates Of The Capacitor, Would Be, Respectively. - P1 Year:2019 - Neet-xii-physics

Home Learn Fast select Course

Show Unit/Chapter Change Unit Change Subject Last Menu

NEET-XII-Physics

P1 year:2019

with Solutions - page 4

Qstn# 43 Prvs-Qstn Next-Qstn

#43
A parallel plate capacitor of capacitance 20 μF
is being charged by a voltage source whose
potential is changing at the rate of 3 V/s. The
conduction current through the connecting
wires, and the displacement current through
the plates of the capacitor, would be,
respectively.
(1) Zero, 60 μA
(2) 60 μA, 60 μA
(3) 60 μA, zero
(4) Zero, zero
digAnsr: 2
Ans : ( 2 )
Sol. Capacitance of capacitor C = 20 μF
= 20 × 10-6 F
Rate of change of potential
  = 
 
dV
3 v/s
dt
q = CV
=dq dVC
dt dt
i
c
= 20 × 10-6 × 3
= 60 × 10-6 A
= 60 μA
As we know that i
d
= i
c
= 60 μA