NEET-XII-Physics

P1 year:2019

with Solutions - page 3
  • #38
    A small hole of area of cross-section 2`` mm^2`` is
    present near the bottom of a fully filled open
    tank of height 2 m. Taking g = 10 m/``s^2``, the rate
    of flow of water through the open hole would
    be nearly
    (1) 12.6 × ``10^{-6} m^3/s``
    (2) 8.9 × ``10^{-6} m^3/s``
    (3) 2.23 × ``10^{-6} m^3/s``
    (4) 6.4 × ``10^{-6} m^3/s``
    digAnsr:   1
    Ans : ( 1 )
    Sol.
    2 m
    a = 2 mm
    2
    Rate of flow liquid
    = =Q au a 2gh
    =    6 22 10 m 2 10 2 m/s
    = 2 × 2 × 3.14 × 10-6 m3/s
    = 12.56 × 10-6 m3/s
    = 12.6 × 10-6 m3/s