NEET-XII-Physics
P1 year:2019
- #38A small hole of area of cross-section 2`` mm^2`` is
present near the bottom of a fully filled open
tank of height 2 m. Taking g = 10 m/``s^2``, the rate
of flow of water through the open hole would
be nearly
(1) 12.6 × ``10^{-6} m^3/s``
(2) 8.9 × ``10^{-6} m^3/s``
(3) 2.23 × ``10^{-6} m^3/s``
(4) 6.4 × ``10^{-6} m^3/s``digAnsr: 1Ans : ( 1 )
Sol.
2 m
a = 2 mm
2
Rate of flow liquid
= =Q au a 2gh
ï€= ï‚´ ï‚´ ï‚´ ï‚´6 22 10 m 2 10 2 m/s
= 2 × 2 × 3.14 × 10-6 m3/s
= 12.56 × 10-6 m3/s
= 12.6 × 10-6 m3/s