NEET-XII-Physics

P1 year:2019

with Solutions - page 2
  • #30
    When an object is shot from the bottom of a
    long smooth inclined plane kept at an angle 60°
    with horizontal, it can travel a distance ``x_1``
    along the plane. But when the inclination is
    decreased to 30° and the same object is shot
    with the same velocity, it can travel ``x_2``
    distance. Then ``x_1 : x_2`` will be:
    (1) 1 : ``\sqrt2``
    (2) ``\sqrt2`` : 1
    (3) 1 : ``\sqrt3``
    (4) 1 : 2``\sqrt3``
    digAnsr:   3
    Ans : ( 3 )
    Sol.
    60°
    g sin60°
    30°
    g sin30°
    u
    u
    (Stopping distance) = 
    2
    1
    u
    x
    2gsin60
    (Stopping distance) = 
    2
    2
    u
    x
    2gsin30
    &implies;
     = = =
     
    1
    2
    x sin30 1 2
    1: 3
    x sin60 2 3