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NEET-XII-Physics

P1 year:2019

with Solutions - page 2
Qstn# 22 Prvs-QstnNext-Qstn
  • #22
    A force F = 20 + 10 y acts on a particle in y-
    direction where F is in newton and y in meter.
    Work done by this force to move the particle
    from y = 0 to y = 1 m is
    (1) 30 J
    (2) 5 J
    (3) 25 J
    (4) 20 J
    digAnsr:   3
    Ans : ( 3 )
    Sol. Work done by variable force is
    f
    i
    y
    y
    W Fdy= 
    Here, y
    i
    = 0, y
    f
    = 1 m
    ∴
    1
    1 2
    0
    0
    10y
    W (20 10y)dy 20y
    2
     
    = + = + 
     
    = 25 J