NEET-XII-Physics

exam-1 year:2016

with Solutions -
  • #10
    A uniform rope of length L and mass ``m_1`` hangs
    vertically from a rigid support. A block of mass
    ``m_2`` is attached to the free end of the rope.
    A transverse pulse of wavelength ``\lambda_1`` is produced
    at the lower end of the rope. The wavelength of
    the pulse when it reaches the top of the rope is
    ``\lambda_2``. The ratio ``\lambda_2``/``\lambda_1`` is :
    (1)``\sqrt\frac {m_1}{m_2}``
    (2)``\sqrt\frac {m_1 + m_2}{m_2}``
    (3)``\sqrt\frac {m_2}{m_1}``
    (4)``\sqrt\frac {m_1 + m_2}{m_1}``
    digAnsr:   2
    Ans : 2
    Sol. T1 = m2g
    L
    T2
    m1
    T1
    m2
    T2 = (m1 + m2)g
    Velocity  T
     T
    11
    2 2
    T
    T

    =

    &implies;
     +
    =

    2 1 2
    1 2
    m m
    m