NEET-XII-Physics
exam-1 year:2016
- #10A uniform rope of length L and mass ``m_1`` hangs
vertically from a rigid support. A block of mass
``m_2`` is attached to the free end of the rope.
A transverse pulse of wavelength ``\lambda_1`` is produced
at the lower end of the rope. The wavelength of
the pulse when it reaches the top of the rope is
``\lambda_2``. The ratio ``\lambda_2``/``\lambda_1`` is :
(1)``\sqrt\frac {m_1}{m_2}``
(2)``\sqrt\frac {m_1 + m_2}{m_2}``
(3)``\sqrt\frac {m_2}{m_1}``
(4)``\sqrt\frac {m_1 + m_2}{m_1}``digAnsr: 2Ans : 2
Sol. T1 = m2g
L
T2
m1
T1
m2
T2 = (m1 + m2)g
Velocity T
T
11
2 2
T
T
=
&implies;
+
=
2 1 2
1 2
m m
m