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NEET-XII-Physics

exam-1 year:2016

with Solutions -
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  • #2
    A square loop ABCD carrying a current i, is placed
    near and coplanar with a long straight conductor
    XY carrying a current I, the net force on the loop
    will be :-

    (1) ``\frac {2\mu_0 Ii}{3\pi}``
    (2)``\frac {\mu_0 Ii}{2\pi}``
    (3) ``\frac {2\mu_0 IiL}{3\pi}``
    (4)``\frac {\mu_0 IiL}{2\pi}``
    digAnsr:   1
    Ans : 1
    Sol.
    FAB FCD
    FBC
    FAD
    A D
    CB
    I
    L
    Li
    FAB = iB (Attractive)
    FAB = i(L).
     
     
     
    0µ I
    L
    2
    2
    () =

    0µ iI ()
    FBC () and FAD () &implies;cancels each other
    FCD = iB (Repulsive)
    FCD = i(L)
     
     
     
    0µ I
    3L
    2
    2
    () =

    0µ iI
    3
    ()
    &implies; Fnet = 
    0µ iI -

    0µ iI
    3
    =

    02µ iI
    3