NEET-XII-Physics

exam-1 year:2016

with Solutions - page 3
  • #43
    A small signal voltage V(t) = ``V_0 ``sin``\omega``t is applied
    across an ideal capacitor C :-
    (1) Current I (t), lags voltage V(t) by 90°.
    (2) Over a full cycle the capacitor C does not
    consume any energy from the voltage source.
    (3) Current I (t) is in phase with voltage V(t).
    (4) Current I (t) leads voltage V(t) by 180°.
    digAnsr:   2
    Ans : 2
    Sol. Power = Vrms . Irms cos
    as cos = 0 (Because  = 90°)
    ∴ Power consumed = 0 (in one complete cycle)