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NEET-XII-Physics

exam-1 year:2016

with Solutions - page 3
Qstn# 41 Prvs-QstnNext-Qstn
  • #41
    If the velocity of a particle is v = At + ``Bt^2``, where
    A and B are constants, then the distance travelled
    by it between 1s and 2s is :-
    (1) 3/2 A + 4B
    (2) 3A+7B
    (3)3/2 A + 7/3 B
    (4)A/2 + B\3
    digAnsr:   3
    Ans : 3
    Sol. V = At + Bt2 &implies; = + 2
    dx
    At Bt
    dt
    &implies; 
    x
    0
    dx = +
    2
    2
    1
    (At Bt )dt
    &implies; x =  + 2 2 3 3
    A B
    (2 1 ) (2 1 )
    2 3
    = +
    3A 7B
    2 3