NEET-XII-Physics
exam-1 year:2016
- #38Given the value of Rydberg constant is ``10^7m^{-1}``, the
wave number of the last line of the Balmer series
in hydrogen spectrum will be :-
(1) 0.025 × ``10^4m^{-1}``
(2) 0.5 × ``10^7m^{-1}``
(3) 0.25 × ``10^7m^{-1}``
(4) 2.5 × ``10^7m^{-1}``digAnsr: 3Ans : 3
Sol.
1
= RZ2
2 2
2 1
1 1
n n
= 107 × 12
2 2
1 1
2
&implies; wave number =
1
= 0.25 × 107 m-1