NEET-XII-Physics

exam-1 year:2016

with Solutions - page 3
  • #38
    Given the value of Rydberg constant is ``10^7m^{-1}``, the
    wave number of the last line of the Balmer series
    in hydrogen spectrum will be :-
    (1) 0.025 × ``10^4m^{-1}``
    (2) 0.5 × ``10^7m^{-1}``
    (3) 0.25 × ``10^7m^{-1}``
    (4) 2.5 × ``10^7m^{-1}``
    digAnsr:   3
    Ans : 3
    Sol.

    1
    = RZ2
     
     
     
    2 2
    2 1
    1 1
    n n
    = 107 × 12
     
      
    2 2
    1 1
    2
    &implies; wave number =

    1
    = 0.25 × 107 m-1