NEET-XII-Physics

exam-1 year:2016

with Solutions - page 3
  • #31
    A potentiometer wire is 100 cm long and a constant
    potential difference is maintained across it. Two
    cells are connected in series first to support one
    another and then in opposite direction. The balance
    points are obtained at 50 cm and 10 cm from the
    positive end of the wire in the two cases. The ratio
    of emf's is :-
    (1) 5 : 1
    (2) 5 : 4
    (3) 3 : 4
    (4) 3 : 2
    digAnsr:   4
    Ans : 4
    Sol.
    +
    =
    
    1 2
    1 2
    E E 50
    E E 10
    &implies;
    +
    =
    
    1
    2
    2E 50 10
    2E 50 10
    &implies; =1
    2
    E 3
    E 2