NEET-XII-Physics
exam-1 year:2016
- #29When a metallic surface is illuminated with radiation
of wavelength ``\lambda``, the stopping potential is V. If the
same surface is illuminated with radiation of
wavelength 2``\lambda``, the stopping potential is V/4. The
threshold wavelength for the metallic surface is :-
(1) 4``\lambda``
(2) 5``\lambda``
(3) 5/2 ``\lambda``
(4) 3 ``\lambda``digAnsr: 4Ans : 4
Sol. eV =
0
hc hc
...(i)
eV/4 =
0
hc hc
2
...(ii)
From equation (i) and (ii)
&implies; 4 =
0
0
1 1
1 1
2
On solving 0 = 3