NEET-XII-Physics

exam-1 year:2016

with Solutions - page 2
  • #29
    When a metallic surface is illuminated with radiation
    of wavelength ``\lambda``, the stopping potential is V. If the
    same surface is illuminated with radiation of
    wavelength 2``\lambda``, the stopping potential is V/4. The
    threshold wavelength for the metallic surface is :-
    (1) 4``\lambda``
    (2) 5``\lambda``
    (3) 5/2 ``\lambda``
    (4) 3 ``\lambda``
    digAnsr:   4
    Ans : 4
    Sol. eV = 
     0
    hc hc
    ...(i)
    eV/4 = 
     0
    hc hc
    2
    ...(ii)
    From equation (i) and (ii)
    &implies; 4 =

     

     
    0
    0
    1 1
    1 1
    2
    On solving 0 = 3