NEET-XII-Physics

exam-1 year:2016

with Solutions - page 2
  • #20
    An electron of mass m and a photon have same
    energy E. The ratio of de-Broglie wavelengths
    associated with them is :
    (1)``\frac 1c(\frac{E}{2m})^\frac 12``
    (2)``(\frac{E}{2m})^\frac 12``
    (3) ``c(2mE)^\frac 12``
    (4) ``\frac {1}{xc}(\frac{2m}{E})^\frac 12``
    (c being velocity of light)
    digAnsr:   1
    Ans : 1
    Sol. For electron e =
    h
    2mE
    for Photon E = pc &implies;  =Ph
    hc
    E
    &implies;
      
    =  =    
    1/2
    e
    Ph
    h E E 1
    hc 2m c2mE