NEET-XII-Physics
exam-1 year:2016
- #20An electron of mass m and a photon have same
energy E. The ratio of de-Broglie wavelengths
associated with them is :
(1)``\frac 1c(\frac{E}{2m})^\frac 12``
(2)``(\frac{E}{2m})^\frac 12``
(3) ``c(2mE)^\frac 12``
(4) ``\frac {1}{xc}(\frac{2m}{E})^\frac 12``
(c being velocity of light)digAnsr: 1Ans : 1
Sol. For electron e =
h
2mE
for Photon E = pc &implies; =Ph
hc
E
&implies;
= =
1/2
e
Ph
h E E 1
hc 2m c2mE