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NEET-XII-Physics
exam-1 year:2016
- #17A npn transistor is connected in common emitter
configuration in a given amplifier. A load resistance
of 800 ``\Omega`` is connected in the collector circuit and
the voltage drop across it is 0.8 V. If the current
amplification factor is 0.96 and the input resistance
of the circuit is 192``\Omega``, the voltage gain and the
power gain of the amplifier will respectively be :
(1) 4, 3.84
(2) 3.69, 3.84
(3) 4, 4
(4) 4, 3.69digAnsr: 1Ans : 1
Sol. Given = 0.96
so, =
=
0.96
1 0.04
&implies; = 24
Voltage gain for common emitter configuration
Av = .
L
i
R
R = 24 ×
=
800
100
192
Power gain for common emitter configuration
Pv = Av = 24 × 100 = 2400
Voltage gain for common base configuration
Av = .
L
P
R
R = 0.96 ×
800
192
= 4
Power gain for common base configuration
Pv = Av = 4 × 0.96 = 3.84
*In the question it is asked about common
emitter configuration but we got above
answer for common base configuration.