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NEET-XII-Physics

exam-1 year:2016

with Solutions - page 2
  • #17
    A npn transistor is connected in common emitter
    configuration in a given amplifier. A load resistance
    of 800 ``\Omega`` is connected in the collector circuit and
    the voltage drop across it is 0.8 V. If the current
    amplification factor is 0.96 and the input resistance
    of the circuit is 192``\Omega``, the voltage gain and the
    power gain of the amplifier will respectively be :
    (1) 4, 3.84
    (2) 3.69, 3.84
    (3) 4, 4
    (4) 4, 3.69
    digAnsr:   1
    Ans : 1
    Sol. Given  = 0.96
    so,  =

    =
     
    0.96
    1 0.04
    &implies;  = 24
    Voltage gain for common emitter configuration
    Av = .
    L
    i
    R
    R = 24 ×
    =
    800
    100
    192
    Power gain for common emitter configuration
    Pv = Av = 24 × 100 = 2400
    Voltage gain for common base configuration
    Av = .
    L
    P
    R
    R = 0.96 ×
    800
    192
    = 4
    Power gain for common base configuration
    Pv = Av = 4 × 0.96 = 3.84
    *In the question it is asked about common
    emitter configuration but we got above
    answer for common base configuration.