NEET-XII-Physics

pp year:2018

with Solutions -
  • #14
    A carbon resistor (47 ``\pm``4.7) ``k\Omega `` is to be
    marked with rings of different colours for its
    identification. The colour code sequence will be :-
    (1) Violet - Yellow - Orange - Silver
    (2) Yellow - Violet - Orange - Silver
    (3) Yellow - Green - Violet - Gold
    (4) Green - Orange - Violet - Gold
    digAnsr:   2
    Ans : (2)
    Sol. =   3R (47 4.7) 10
    =   3R 47 10 10%
    As per color code, 3 - Orange, 4 - Yellow, 7 - Violet,
    10% - Silver