NEET-XII-Chemistry
exam-1 year:2016
- #75The pressure of ``H_2`` required to make the potential
of ``H_2``-electrode zero in pure water at 298 K is :-
(1) ``10^{-14}`` atm
(2) ``10^{-12}`` atm
(3) ``10^{-10}`` atm
(4) ``10^{-4}`` atmdigAnsr: 1Ans : (1)
Sol. 2H+(aq) + 2e- H2(g)
+
∴ = 2
H0
2
P0.0591
E E log
2 H
0 = 0- 0.0295 log
2H
27
P
10
2H
27
P
10
=1
=
2
14
HP 10 atm