NEET-XII-Chemistry

Previous Year Paper year:2018

with Solutions -
  • #59
    Iron exhibits bcc structure at room temperature.
    Above 900°C, it transforms to fcc structure. The
    ratio of density of iron at room temperature to that
    at 900°C (assuming molar mass and atomic radii of
    iron remains constant with temperature) is
    (1)``\frac{\sqrt3}{\sqrt2}``
    (2)``\frac{4\sqrt3}{3\sqrt2}``
    (3)``\frac{3\sqrt3}{4\sqrt2}``
    (4)``\frac{1}{2}``
    digAnsr:   3
    Ans : (3)
    Sol. BCC FCC
    4r = 3a 4r = 2a
    a =
    4r
    3
    a =
    4r
    2
    BCC
    FCC
    d
    d =


    BCC
    3
    A
    FCC
    3
    A
    Z M
    N a
    Z M
    N a
    =
    3
    A
    3
    A
    2 M
    4r
    N
    3
    4 M
    4r
    N
    2

     
     
     

     
     
     
    =
    3 3
    4 2