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NEET-XII-Chemistry

Previous Year Paper year:2018

with Solutions -
Qstn# 56 Prvs-QstnNext-Qstn
  • #56
    Consider the change in oxidation state of Bromine
    corresponding to different emf values as shown in
    the diagram below:
    n56.png
    Then the species undergoing disproportionation is:-
    (1) ``\ce{BrO3-}``
    (2) ``\ce{BrO4-}``
    (3) ``\ce{Br2}``
    (4) HBrO
    digAnsr:   4
    Ans : (4)
    Sol. Calculate E°cell corresponding to each compound
    under going disproportionation reaction. The
    reaction for which E°cell comes out +ve is
    spontaneous.
    HBrO  Br2 E° = 1.595, SRP (cathode)
    HBrO  BrO3
    - E° = -1.5V, SOP (Anode)
    2HBrO  Br2 + BrO3
    -
    E°cell = SRP (cathode) - SRP (Anode)
    = 1.595 - 1.5
    = 0.095 V
    E°cell > 0 &implies; ▵G° < 0 [spontaneous]