NEET-XII-Chemistry

Previous Year Paper year:2018

with Solutions - page 2
  • #74
    The compound ``\ce C7H8 ``undergoes the following
    reactions :
    ``\ce{$C7H8$ ->[\ce{ \frac {3Cl_2}{\lambda}}] $A$} ``
    ``\ce{$$ ->[\ce{\frac {Br_2}{Fe}}] $B$} \\``
    ``\ce{$$ ->[\ce{\frac {Zn}{HCl}}] $C$} \\``
    The product 'C' is
    (1) m-bromotoluene
    (2) o-bromotoluene
    (3) 3-bromo-2,4,6-trichlorotoluene
    (4) p-bromotoluene
    digAnsr:   1
    Ans : (1)
    Sol.
    CH3
    
    3Cl2
    â–µ
    CCl3
    
    Br2
    Fe
    CCl3
    Zn
    HCl
    Br
    CH3
    Br
    m-bromotoluene