NEET-XII-Chemistry
Previous Year Paper year:2018
- #74The compound ``\ce C7H8 ``undergoes the following
reactions :
``\ce{$C7H8$ ->[\ce{ \frac {3Cl_2}{\lambda}}] $A$} ``
``\ce{$$ ->[\ce{\frac {Br_2}{Fe}}] $B$} \\``
``\ce{$$ ->[\ce{\frac {Zn}{HCl}}] $C$} \\``
The product 'C' is
(1) m-bromotoluene
(2) o-bromotoluene
(3) 3-bromo-2,4,6-trichlorotoluene
(4) p-bromotoluenedigAnsr: 1Ans : (1)
Sol.
CH3

3Cl2
â–µ
CCl3

Br2
Fe
CCl3
Zn
HCl
Br
CH3
Br
m-bromotoluene