NEET-XII-Chemistry
Previous Year Paper year:2018
- #69Following solutions were prepared by mixing
different volumes of NaOH and HCl of different
concentrations :
a. 60mL ``\frac{M}{10}``HCl +
40mL ``\frac{M}{10}`` NaOH
b. 55mL ``\frac{M}{10}``HCl +
45mL ``\frac{M}{10}`` NaOH
c. 75mL ``\frac{M}{5}``HCl +
25mL ``\frac{M}{5}`` NaOH
d. 100mL ``\frac{M}{10}``HCl +
100mL ``\frac{M}{10}`` NaOH
pH of which one of them will be equal to 1 ?
(1) b
(2) a
(3) d
(4) cdigAnsr: 4Ans : (4)
Sol. As N1V1 > N2V2
So acid is left at the end of reaction
Nfinal solution = [H
+] =
1 1 2 2
1 2
N V N V
V V
+
=
1 1
75 25
5 5
75 25
+
=
1
0.1
10
=
pH = -log[H+] = 1
14
NEET(UG)-2018