NEET-XII-Chemistry

Previous Year Paper year:2018

with Solutions - page 2
  • #69
    Following solutions were prepared by mixing
    different volumes of NaOH and HCl of different
    concentrations :
    a. 60mL ``\frac{M}{10}``HCl +
    40mL ``\frac{M}{10}`` NaOH
    b. 55mL ``\frac{M}{10}``HCl +
    45mL ``\frac{M}{10}`` NaOH
    c. 75mL ``\frac{M}{5}``HCl +
    25mL ``\frac{M}{5}`` NaOH
    d. 100mL ``\frac{M}{10}``HCl +
    100mL ``\frac{M}{10}`` NaOH
    pH of which one of them will be equal to 1 ?
    (1) b
    (2) a
    (3) d
    (4) c
    digAnsr:   4
    Ans : (4)
    Sol. As N1V1 > N2V2
    So acid is left at the end of reaction
    Nfinal solution = [H
    +] =
    1 1 2 2
    1 2
    N V N V
    V V

    +
    =
    1 1
    75 25
    5 5
    75 25
      
    +
    =
    1
    0.1
    10
    =
    pH = -log[H+] = 1
    
    
    14
    NEET(UG)-2018