Find out the solubility of ``\ce{Ni(OH)2}``
in 0.1 M NaOH.
Given that the ionic product of ``\ce{Ni(OH)2}``
is
2×``10^{-15}``.
(1) 2×``10^{-13}`` M
(2) 2×``10^{-8}`` M
(3) 1×``10^{-13}`` M
(4) 1×``10^{8}`` M