NEET-XII-Chemistry

04: Amines

page 2

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  • Qstn #4-iii
    CH3NH2, (CH3)2NH, (CH3)3N, C6H5NH2, C6H5CH2NH2.




    Ans : Considering the inductive effect and the steric hindrance of alkyl groups, CH3NH2, (CH3)2NH, and (CH3)3N can be arranged in the increasing order of their basic strengths as:



    In C6H5NH2, N is directly attached to the benzene ring. Thus, the lone pair of electrons on the N-atom is delocalized over the benzene ring. In C6H5CH2NH2, N is not directly attached to the benzene ring. Thus, its lone pair is not delocalized over the benzene ring. Therefore, the electrons on the N atom are more easily available for protonation in C6H5CH2NH2 than in C6H5NH2 i.e., C6H5CH2­NH2 is more basic than C6H5NH2.

    Again, due to the -I effect of C6H5 group, the electron density on the N-atom in C6H5CH2NH2 is lower than that on the N-atom in (CH3)3N. Therefore, (CH3)3N is more basic than C6H5CH2NH2. Thus, the given compounds can be arranged in the increasing order of their basic strengths as follows.


  • Qstn #5
    Complete the following acid-base reactions and name the products:
  • Qstn #5-ii
    (C2H5)3N + HCl


    Ans : C2H53NTriethylamine+HCl→C2H53N+HCl-Triethylammoniumchloride
  • Qstn #6
    Write reactions of the final alkylation product of aniline with excess of methyl

    iodide in the presence of sodium carbonate solution.
    Ans : Aniline reacts with methyl iodide to produce N, N-dimethylaniline.



    With excess methyl iodide, in the presence of Na2CO3 solution, N, N-dimethylaniline produces N, N, N-trimethylanilinium carbonate.


  • Qstn #7
    Write chemical reaction of aniline with benzoyl chloride and write the name of

    the product obtained.
    Ans :
  • Qstn #8
    Write structures of different isomers corresponding to the molecular formula,

    C3H9N. Write IUPAC names of the isomers which will liberate nitrogen gas on

    treatment with nitrous acid.
    Ans : The structures of different isomers corresponding to the molecular formula, C3H9N are given below:

    (a)

    Propan-1-amine (10)

    (b)



    Propan-2-amine (10)

    (c)



    (d)



    N,N-Dimethylmethanamine (30)

    10amines, (a) propan-1-amine, and (b) Propan-2-amine will liberate nitrogen gas on treatment with nitrous acid.





    SECTION I SECTION I Page No 399:
  • Qstn #9-i
    3-Methylaniline into 3-nitrotoluene.
    Ans :
  • Qstn #9-ii
    Aniline into 1,3,5-tribromobenzene.
    Ans :
  • #
    Section : II
    SECTION I Page No 400:
  • Qstn #1
    Write IUPAC names of the following compounds and classify them into primary,

    secondary and tertiary amines.
  • Qstn #1-i
    (CH3)2 CHNH2
    Ans : 1-Methylethanamine (10 amine)
  • Qstn #1-ii
    CH3(CH2)2NH2
    Ans : Propan-1-amine (10 amine)
  • Qstn #1-iii
    CH3NHCH(CH3)2
    Ans : N-Methyl-2-methylethanamine (20 amine)