NEET-XI-Chemistry

05: Organic Chemistry: Some Basic Principles and Techniques

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  • #3-a
    Isopropyl alcohol,
    Ans : Isopropyl alcohol


  • #3-b
    2,3-Dimethyl butanal,
    Ans : 2, 3-dimethyl butanal


  • #3-c
    Heptan-4-one.
    Ans : Heptan-4-one


  • Qstn #4
    Give the IUPAC names of the following compounds:
  • #4-a

    Ans :

    1-phenyl propane
  • #4-b

    Ans :

    3-methylpentanenitrile
  • #4-c

    Ans :

    2, 5-dimethyl heptane
  • #4-d

    Ans :

    3-bromo-3-chloroheptane
  • #4-e

    Ans :

    3-chloropropanal
  • #4-f
    Cl2CHCH2OH
    Ans : Cl2CHCH2OH

    2,2- Dichloroethanol
  • Qstn #5
    Which of the following represents the correct IUPAC name for the compounds concerned? (a) 2,2-Dimethylpentane or 2-Dimethylpentane (b) 2,4,7-Trimethyloctane or 2,5,7-Trimethyloctane (c) 2-Chloro-4-methylpentane or 4-Chloro-2-methylpentane (d) But-3-yn-1-ol or But-4-ol-1-yne
    Ans : -(a) The prefix di in the IUPAC name indicates that two identical substituent groups are present in the parent chain. Since two methyl groups are present in the C-2 of the parent chain of the given compound, the correct IPUAC name of the given compound is 2, 2-dimethylpentane.

    (b) Locant number 2, 4, 7 is lower than 2, 5, 7. Hence, the IUPAC name of the given compound is 2, 4, 7-trimethyloctane.

    (c) If the substituents are present in the equivalent position of the parent chain, then the lower number is given to the one that comes first in the name according to the alphabetical order. Hence, the correct IUPAC name of the given compound is 2-chloro-4-methylpentane.

    (d) Two functional groups - alcoholic and alkyne - are present in the given compound. The principal functional group is the alcoholic group. Hence, the parent chain will be suffixed with ol. The alkyne group is present in the C-3 of the parent chain. Hence, the correct IUPAC name of the given compound is But-3-yn-1-ol.
  • Qstn #6
    Draw formulas for the first five members of each homologous series beginning with the following compounds.
    Ans : The first five members of each homologous series beginning with the given compounds are shown as follows:
  • #6-a
    H-COOH
    Ans : H-COOH : Methanoic acid

    CH3-COOH : Ethanoic acid

    CH3-CH2-COOH : Propanoic acid

    CH3-CH2-CH2-COOH : Butanoic acid

    CH3-CH2-CH2-CH2-COOH : Pentanoic acid
  • #6-b
    CH3COCH3
    Ans : CH3COCH3 : Propanone

    CH3COCH2CH3 : Butanone

    CH3COCH2CH2CH3 : Pentan-2-one

    CH3COCH2CH2CH2CH3 : Hexan-2-one

    CH3COCH2CH2CH2CH2CH3 : Heptan-2-one
  • #6-c
    H-CH=CH2
    Ans : H-CH=CH2 : Ethene

    CH3-CH=CH2 : Propene

    CH3-CH2-CH=CH2 : 1-Butene

    CH3-CH2-CH2-CH=CH2: 1-Pentene

    CH3-CH2-CH2-CH2-CH=CH2 : 1-Hexene