ICSE-X-Physics
Previous Year Paper year:2017
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- #2-d-iivelocity of light in vacuum or air and the velocity of light in a given medium?Ans : Refractive index is the ratio of the velocity of light in vacuum to the
velocity of light in a medium.
``\mu = \frac{c}{v}``
- #2-e [2]State the conditions required for total internal reflection of light to take place.Ans : Conditions necessary for total internal reflection to take place are
(i) Light must travel from a denser medium to a rarer medium.
(ii) Angle of incidence must be greater than the critical angle for the pair of media
- #3
- #3-a [2]Draw a ray diagram to show the refraction of a monochromatic ray through a prism when it suffers minimum deviation.Ans : Refraction of a monochromatic ray through a prism when it goes through
minimum deviation:
- #3-b [2]The human ear can detect continuous sounds in the frequency range from ``\pu{20 Hz}`` to ``\pu{20,000 Hz}``. Assuming that the speed of sound in air is ``\pu{330 ms-1}`` for all frequencies; calculate the wavelengths corresponding to the given extreme frequencies of the audible range.Ans : Audible range of hearing for a normal human ear is 20 Hz to 20,000 Hz.
Speed of sound in air, v = 330 m/s
Speed, wavelength and frequency are related as
$$v=\nu\lambda$$
$$\lambda =\frac{v}{\nu}$$
$$\nu_{lower} = \pu{20 Hz};$$
$$\lambda_{lower} = \frac{330}{20) = 16.5 m$$
similarly
``\nu_{higher} = \pu{20 Hz};``
$$\lambda_{higher} = \frac{330}{20000} (*1000)= 16.5 mm$$
- #3-c [2]An enemy plane is at a distance of 300 km from a radar. In how much time the
radar will be able to detect the plane? Take velocity of radio waves as ``\pu{3E8 ms-1}``.Ans : Distance between the plane and the radar:
d = 300 km = ``\pu{300E3 m} = \pu{3E5 m }``
Velocity of radio waves, c = ``\pu{3E8 ms^-1}``
Since Waves from the radar will travel to the plane(d) and
then reflect and travel backto the receiver of the radar(d). Hence,
the total distance travelled by the waves = 2d .
$$2d = c*t$$
$$2d/c = t$$
$$t = \frac{2*\pu{3E5}}{\pu{3E8}}$$
$$t = \pu{2E-3} * 1000 = \pu{2ms}$$
- #3-d [2]How is the frequency of a stretched string related to:
- #3-d-iit’s length?Ans : Frequency of a stretched string is inversely proportional to its length.
$$f \propto \frac{1}{L}$$
- #3-d-iiit’s tension?Ans : Frequency of a stretched string is directly proportional to the square root
of the tension in the string.
$$f \propto \sqrt T$$
- #3-e [2]Define specific resistance and state its SI unit.Ans : Specific resistance or resistivity of a material is the resistance of a wire of
that material of unit length and unit area of cross-section.
Its SI unit is ``\pu{ohm metre (\Omega m)}``.
- #4
- #4-a [2]An electric bulb of ``\pu{300 \Omega}`` draws a current of ``\pu{0.4 A}``. Calculate the power of the bulb and the potential difference at its ends.Ans : Current drawn by the bulb, I = 0.4 A
Resistance of the bulb, R = 300 ``\Omega``
Power of the bulb is:
``p= i^2r``
so, ``P = (0.4)^2 * 300 = 48 W``
Potential difference at the ends of the bulb is
V = IR
V= 0.4 * 300 = 120 V
- #4-b [2]State two causes of energy loss in a transformer.Ans : Causes of energy loss in a transformer:
(i) Eddy currents developed in the core.
(ii) Hysteresis loss because of repeated magnetisation and demagnetisation
of the iron core.
- #4-c [2]State two characteristics of a good thermion emitter.Ans : Characteristics of a good thermion emitter:
(i) The work function of the substance should be low so that electrons may be emitted from it even when it is not heated to a high temperature.
(ii) The melting point of the substance should be high so that it may not melt
when it is heated to the temperature required for thermionic emission.
- #4-d [2]State two factors upon which the rate of emission of thermions depends.Ans : Factors on which the rate of emission of thermions depend:
(i) Nature of the metal surface: Lower the work function of the metal,
greater is the rate of emission of electrons.
(ii) Temperature of the surface: Higher the temperature of the surface, greater is the rate of emission of electrons.