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ICSE-VIII-Mathematics

23: Probability Class 8 Maths

with Solutions - page 2

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  • #6-i
    greater than 2
    Ans : A die has six numbers = 1, 2, 3, 4, 5, 6
    ∴ Number of possible outcomes = 6
    ∴ P(E) = 4/6 = 2/3
  • #6-ii
    less than or equal to 2
    Ans : Less than or equal to 2
    Number of favourable outcome = 1, 2
    ∴ P(E) = 2/6
    = 1/3
  • #6-iii
    not greater than 2.
    Ans : Not greater than 2
    Number of favourable outcomes = 1, 2
    ∴ P(E) = 2/6
    = 1/3
  • Qstn #7
    A bag contains 3 white, 5 black and 2 red balls, all of the same shape and size.
    A ball is drawn from the bag without looking into it, find the probability that the ball drawn is:
    Ans : In a bag, 3 balls are white
    2 balls are red
    5 balls are black
    Total number of balls = 3 + 2 + 5 = 10
  • #7-i
    (a) black ball.
    Ans : Numbers of possible outcome of one black ball = 10
    And number of favourable outcome of one black ball = 5
    ∴ P(E) = (Number of favourable outcome)/(Number of all possible outcome)
    = 5/10
    = 1/2
  • #7-ii
    (a) red ball.
    Ans : Number of possible outcome of one red ball = 10
    And number of favourable outcome = 2
    ∴ P(E) = (Number of favourable outcome)/(Number of all possible outcome)
    = 2/10
    = 1/5
  • #7-iii
    (a) white ball.
    Ans : Number of possible outcome of white ball = 10
    And number of favourable outcome = 3
    ∴ P(E) = (Number of favourable outcome)/(Number of all possible outcome)
    = 3/10
  • #7-iv
    not a red ball.
    Ans : Number of possible outcome = 10
    Number of favourable outcome = 3 + 5 = 8
    Not a red ball
    ∴ P(E) = (Number of favourable outcome)/(Number of all possible outcome)
    = 8/10
    = 4/5
  • #7-v
    not a black ball.
    Ans : Number of possible outcomes = 10
    Number of favourable outcome not a black ball = 3 + 2 = 5
    ∴ P(E) = (Number of favourable outcome)/(Number of all possible outcome) = 5/10
    = 1/2
  • Qstn #8
    In a single throw of a die, find the probability that the number:
    Ans : A die has six numbers : 1, 2, 3, 4, 5, 6
    ∴ Number of possible outcome = 6
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  • #8-i
    will be an even number.
    Ans : Number of favourable outcome = an even number i.e. 2, 4, 6 which are 3 in numbers
    ∴ P(E) = (Numbers of favourable outcome)/(Number of all possible outcome)
    = 3/6
    = 1/2
  • #8-ii
    will be an odd number. (iii) will not be an even number.
    Ans : & (iii) Number of favourable outcome = not an even number i.e. odd numbers : 1, 3, 5 which are 3 in numbers
    ∴ P(E) = (Number of favourable outcome)/(Number of all possible outcome)
    = 3/6
    = 1/2
  • Qstn #9
    In a single throw of a die, find the probability of getting :
    Ans : On a die the numbers are 1, 2, 3, 4, 5, 6 i.e. six.
    ∴ Number of possible outcome = 6
  • #9-i
    8
    Ans : Number of favourable outcome = 0
    (∵ 8 is not possible)
    ∴ P(E) = (Number of favourable outcome)/(Number of all possible outcome)
    = 0/6 = 0
  • #9-ii
    (a) number greater than 8
    Ans : Number greater than 8 will be 0
    ∴ P(E) = (Number of favourable outcome)/(Number of all possible outcome)
    = 0/6
    = 0
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