Qstnid -B-19- The Length And The Breadth Of A Conference Hall Are In The Ratio 7 : 4 And Its Perimeter Is 110 M. Find: (I) Area Of The Floor Of The Hall. (Ii) Number Of Tiles, Each A Rectangle Of Size 25 Cm X 20 Cm, Required For Flooring Of The Hall. (Iii) The Cost Of The Tiles At The Rate Of ₹ 1,400 Per Hundred Tiles. (I) Area Of The Floor Of The Hall. (Ii) Number Of Tiles, Each A Rectangle Of Size 25 Cm X 20 Cm, Required For Flooring Of The Hall. (Iii) The Cost Of The Tiles At The Rate Of ₹ 1,400 Per Hundred Tiles. - 20: Area Of Trapezium And A Polygon Class 8 Maths - Icse-viii-mathematics

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ICSE-VIII-Mathematics

20: Area of Trapezium and a Polygon Class 8 Maths

with Solutions - page 4

Qstn# B-19 Prvs-Qstn Next-Qstn

#19
The length and the breadth of a conference hall are in the ratio 7 : 4 and its perimeter is 110 m. Find: (i) area of the floor of the hall. (ii) number of tiles, each a rectangle of size 25 cm x 20 cm, required for flooring of the hall. (iii) the cost of the tiles at the rate of ₹ 1,400 per hundred tiles. (i) area of the floor of the hall. (ii) number of tiles, each a rectangle of size 25 cm x 20 cm, required for flooring of the hall. (iii) the cost of the tiles at the rate of ₹ 1,400 per hundred tiles.
Ans : Ratio in length and breadth = 7 : 4
Perimeter = 110 m
∴ Length + Breadth = 110/2 = 55m
Sum of ratios = 7 + 4 = 11
∴ Length = (55 × 7)/11
= 35 m
And Breadth = (55 × 4)/11
= 20m (i) Area of floor = l × b
= 35 × 20
= 700 m² (ii) Size of tile = 25 cm × 20 cm
= (25 × 20)/(100 × 100)
= 1/20 m²
∴ Number of tiles = Area of floor/Area of one tile
= (700 × 20)/1
= 14000 (iii) Cost of tiles = ₹1400 per 100 tiles
∴ Total cost = (14000 × 1400)/100
= ₹196000 (i) Area of floor = l × b
= 35 × 20
= 700 m² (ii) Size of tile = 25 cm × 20 cm
= (25 × 20)/(100 × 100)
= 1/20 m²
∴ Number of tiles = Area of floor/Area of one tile
= (700 × 20)/1
= 14000 (iii) Cost of tiles = ₹1400 per 100 tiles
∴ Total cost = (14000 × 1400)/100
= ₹196000

#19-i
area of the floor of the hall.
Ans : Area of floor = l × b
= 35 × 20
= 700 m²

#19-ii
number of tiles, each a rectangle of size 25 cm x 20 cm, required for flooring of the hall.
Ans : Size of tile = 25 cm × 20 cm
= (25 × 20)/(100 × 100)
= 1/20 m²
∴ Number of tiles = Area of floor/Area of one tile
= (700 × 20)/1
= 14000

#19-iii
the cost of the tiles at the rate of ₹ 1,400 per hundred tiles.
Ans : Cost of tiles = ₹1400 per 100 tiles
∴ Total cost = (14000 × 1400)/100
= ₹196000