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ICSE-VIII-Mathematics

20: Area of Trapezium and a Polygon Class 8 Maths

with Solutions - page 3
Qstn# B-2-i Prvs-QstnNext-Qstn
  • #2-i
    breadth (ii) area (iii) diagonal. (ii) area (iii) diagonal.
    Ans : Perimeter of rectangle = 46 m
    length, l = 15 m
    2 (l + b) = 46
    ⇒ 2(15 + b) = 46
    ⇒ 15 + b = 46/2 = 23
    ⇒ b = 23 - 15
    ⇒ b = 8 m (ii) area = l × b = 15 × 8 = 120 m2 (iii) Hence, (i) 8 m(ii)120 m2(iii)17 m (ii) area = l × b = 15 × 8 = 120 m2 (iii) Hence, (i) 8 m(ii)120 m2(iii)17 m
  • #2-ii
    area
    Ans : area = l × b = 15 × 8 = 120 m2
  • #2-iii
    diagonal.
    Ans : Hence, (i) 8 m(ii)120 m2(iii)17 m