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ICSE-VIII-Mathematics

20: Area of Trapezium and a Polygon Class 8 Maths

with Solutions - page 2
Qstn# A-14-i Prvs-QstnNext-Qstn
  • #14-i
    the length of AC. (ii) the area of a ∆ABC (iii) the length of BD, correct to one decimal place.
    Ans :
    (ii) Area of ∆ABC = ½ × AB × BC
    = ½ × 24 × 7
    = 84 cm2 (iii) BD ⊥ AC
    Area ∆ABC = ½ × AC × BD
    84 = ½ × 25 × BD
    ⇒ BD = (84 × 2)/25
    = 168/25
    = 6.72 cm
    = 6.7 cm
  • #14-ii
    the area of a ∆ABC
    Ans : Area of ∆ABC = ½ × AB × BC
    = ½ × 24 × 7
    = 84 cm2
  • #14-iii
    the length of BD, correct to one decimal place.
    Ans : BD ⊥ AC
    Area ∆ABC = ½ × AC × BD
    84 = ½ × 25 × BD
    ⇒ BD = (84 × 2)/25
    = 168/25
    = 6.72 cm
    = 6.7 cm