ICSE-VIII-Mathematics
10: Direct and Inverse Variations Class 8 Maths
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- #Section : A
- #1-iAns : x1/y1 = 3/4.5 = 1/1.5
x2/y2 = 5/7.5 = 1/1.5
x3/y3 = 8/12 = 1/1.5
x4/y4 = 11/16.5 = 1/1.5
⇒ x1/y1 = x2/y2 = x3/y3 = x4/y4
Yes, x and y vary directly.
- #1-iiAns : x1/y1 = 16/32 = ½
x2/y2 = 30/60 = ½
x3/y3 = 40/80 = ½
x4/y4 = 56/84 =28/42 = 14/21 = 7/3
⇒ x1/y1 = x2/y2 = x3/y3 = x4/y4
x and y are not in direct variation.
- #1-iiiAns : x1/y1 = 27/81 = 3/9 = 1/3
x2/y2 = 45/150 = 15/50 = 3/10
x3/y3 = 54/216 = 18/72 = ¼
x4/y4 = 75/225 = 25/45 = 5/9
⇒ x1/y1 ≠x2/y2 ≠x3/y3 ≠x4/y4
x and y are not in direct variation.
- Qstn #2If x and y vary directly, find the values of x, y and z:
Ans : x and y are in direct variation
∴ 3/36 = x/60 = y/96 = 10/z
⇒ 3/36 = x/60, 3/36 = y/96, 3/36 = 10/z
x = 3/36 × 60, y = 3/36 × 96
z = 10 × 36/3
⇒ x = 5, y = 8, z = 120
- Qstn #3A truck consumes 28 litres of diesel for moving through a distance of 448 km. How much distance will it cover in 64 litres of diesel?Ans : Let the truck cover x km in 64 litres of diesel.
It is the case of direct variation
⇒ x1/y1 = x2/y2 = 28/448 = 64/x
i.e., 28x = 64 × 448
⇒ x = (64 × 448)/28
⇒ x = 1024 km
- Qstn #4For 100 km, a taxi charges ₹ 1,800. How much will it charge for a journey of 120 km?Ans : Let a charges of car is ₹ x in 120 km
Since it is the case of direct variation
⇒ x1/y1 = x2/y2
⇒ 1800/100 × x/100
⇒ 100x = 1800 × 120
⇒ x = (1800 × 120)/100
⇒ x = ₹2160
- Qstn #5If 27 identical articles cost ₹ 1,890, how many articles can be bought for ₹ 1,750?Ans : Let x number of articles be purchased in ₹1750
Since, it is a case of direct variation
⇒ 1890/27 = 1750/x
⇒ x = (1750 × 27)/1890
⇒ x = 25 articles
- Qstn #67 kg of rice costs ₹ 1,120. How much rice can be bought for ₹ 3,680?Ans : Rice : Cost :: Rice : Cost
7 kg : ₹1120 : : x kg : ₹3680
∴ x = (7 x 3680)/1120
⇒ x = 23 kg
- Qstn #76 note-books cost ₹ 156, find the cost of 54 such note-books.Ans : Notebooks : Cost :: Notebooks : Cost
6 : ₹156 :: 54 : ₹x
∴ x = (156 × 54)/6
⇒ x = ₹ 1404
- Qstn #822 men can dig a 27 m long trench in one day. How many men should be employed for digging 135 m long trench of the same type in one day?Ans : Men : Length trench :: Men : Length of trench
22 : 27m :: x : 135 m
x = (22 × 135)/27
⇒ x = 110 men
- Qstn #9If the total weight of 11 identical articles is 77 kg, how many articles of the same type would weigh 224 kg?Ans : No. of : Weight :: No. of articles : Weight articles
11 : 77kg :: x : 224 kg
x = (11 × 224)/77
⇒ x = 32 articles