ICSE-VIII-Mathematics
08: Profit, Loss and Discount Class 8 Maths
- #2Find the cost price, if : (i) S.P. = Rs. 1,680 and profit = 12% (ii) S.P. = Rs. 1,128 and loss = 6% (i) S.P. = Rs. 1,680 and profit = 12% (ii) S.P. = Rs. 1,128 and loss = 6%Ans : (i) S.P. = Rs. 1, 128, Profit = 12%
C.P. = 100/(100 + profit) × S.P.
∴ C.P. = 100/(100 + 12) × 1680
= (100 × 1680)/112
= (25 × 1680)/28
= 25 × 60
= Rs. 1500 (ii) S.P. = Rs. 1,128, Loss = 6%
C.P. = 100/(100 - Loss) × S.P.
∴ C.P. = (100 × 1128)/(100 - 6)
= (100 × 1128)/94
= 100 × 12
= Rs. 1200 (i) S.P. = Rs. 1, 128, Profit = 12%
C.P. = 100/(100 + profit) × S.P.
∴ C.P. = 100/(100 + 12) × 1680
= (100 × 1680)/112
= (25 × 1680)/28
= 25 × 60
= Rs. 1500 (ii) S.P. = Rs. 1,128, Loss = 6%
C.P. = 100/(100 - Loss) × S.P.
∴ C.P. = (100 × 1128)/(100 - 6)
= (100 × 1128)/94
= 100 × 12
= Rs. 1200
- #2-iS.P. = Rs. 1,680 and profit = 12%Ans : S.P. = Rs. 1, 128, Profit = 12%
C.P. = 100/(100 + profit) × S.P.
∴ C.P. = 100/(100 + 12) × 1680
= (100 × 1680)/112
= (25 × 1680)/28
= 25 × 60
= Rs. 1500
- #2-iiS.P. = Rs. 1,128 and loss = 6%Ans : S.P. = Rs. 1,128, Loss = 6%
C.P. = 100/(100 - Loss) × S.P.
∴ C.P. = (100 × 1128)/(100 - 6)
= (100 × 1128)/94
= 100 × 12
= Rs. 1200