Qstnid -A-14- A Man Sold His Bicycle For Rs.405 Losing One-tenth Of Its Cost Price, Find : (I) Its Cc Price; (Ii) The Loss Percent. (Ii) The Loss Percent. (Ii) The Loss Percent. - 08: Profit, Loss And Discount Class 8 Maths - Icse-viii-mathematics

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ICSE-VIII-Mathematics

08: Profit, Loss and Discount Class 8 Maths

with Solutions - page 3

Qstn# A-14 Prvs-Qstn Next-Qstn

#14
A man sold his bicycle for Rs.405 losing one-tenth of its cost price, find : (i) its cc price; (ii) the loss percent. (ii) the loss percent. (ii) the loss percent.
Ans : (i) Let C.P. of the bicycle = Rs. x
∴ Loss = Rs. x/10
S.P. = C.P. - Loss
= x - x/10
But, we are given S.P. = Rs. 405
∴ x - x/10 = 405
⇒ (10x - x)/10 = 405
⇒ 9x/10 = 405⇒ x = 405 × 10/9
⇒ x = 4050/9⇒ x = 450
∴ C.P. = Rs. 450 (ii) Loss = x/10
= 450/10 ...(Substituting the value of x)
= Rs. 45
Loss % = Loss/C.P. × 100
= 45/450 × 100
= 4500/450 = 10 % (ii) Loss = x/10
= 450/10 ...(Substituting the value of x)
= Rs. 45
Loss % = Loss/C.P. × 100
= 45/450 × 100
= 4500/450 = 10 % (ii) Loss = x/10
= 450/10 ...(Substituting the value of x)
= Rs. 45
Loss % = Loss/C.P. × 100
= 45/450 × 100
= 4500/450 = 10 %

#14-i
its cc price; (ii) the loss percent. (ii) the loss percent.
Ans : Let C.P. of the bicycle = Rs. x
∴ Loss = Rs. x/10
S.P. = C.P. - Loss
= x - x/10
But, we are given S.P. = Rs. 405
∴ x - x/10 = 405
⇒ (10x - x)/10 = 405
⇒ 9x/10 = 405⇒ x = 405 × 10/9
⇒ x = 4050/9⇒ x = 450
∴ C.P. = Rs. 450 (ii) Loss = x/10
= 450/10 ...(Substituting the value of x)
= Rs. 45
Loss % = Loss/C.P. × 100
= 45/450 × 100
= 4500/450 = 10 % (ii) Loss = x/10
= 450/10 ...(Substituting the value of x)
= Rs. 45
Loss % = Loss/C.P. × 100
= 45/450 × 100
= 4500/450 = 10 %

#14-ii
the loss percent.
Ans : Loss = x/10
= 450/10 ...(Substituting the value of x)
= Rs. 45
Loss % = Loss/C.P. × 100
= 45/450 × 100
= 4500/450 = 10 %