ICSE-VIII-Mathematics
08: Profit, Loss and Discount Class 8 Maths
- #14A man sold his bicycle for Rs.405 losing one-tenth of its cost price, find : (i) its cc price; (ii) the loss percent.Ans : (i) Let C.P. of the bicycle = Rs. x
∴ Loss = Rs. x/10
S.P. = C.P. - Loss
= x - x/10
But, we are given S.P. = Rs. 405
∴ x - x/10 = 405
⇒ (10x - x)/10 = 405
⇒ 9x/10 = 405⇒ x = 405 × 10/9
⇒ x = 4050/9⇒ x = 450
∴ C.P. = Rs. 450 (ii) Loss = x/10
= 450/10 ...(Substituting the value of x)
= Rs. 45
Loss % = Loss/C.P. × 100
= 45/450 × 100
= 4500/450 = 10 %
- #14-iits cc price;Ans : Let C.P. of the bicycle = Rs. x
∴ Loss = Rs. x/10
S.P. = C.P. - Loss
= x - x/10
But, we are given S.P. = Rs. 405
∴ x - x/10 = 405
⇒ (10x - x)/10 = 405
⇒ 9x/10 = 405⇒ x = 405 × 10/9
⇒ x = 4050/9⇒ x = 450
∴ C.P. = Rs. 450
- #14-iithe loss percent.Ans : Loss = x/10
= 450/10 ...(Substituting the value of x)
= Rs. 45
Loss % = Loss/C.P. × 100
= 45/450 × 100
= 4500/450 = 10 %